# benzene is aromatic or not

Huckel's Rule is a set of algorithms that combine the number of $$\pi$$ electrons ($$N$$) and the physical structure of the ring system to determine whether the molecule is aromatic, antiaromatic, or nonaromatic. Note that it now has six electrons in p orbitals perpendicular to the ring -- very similar to pyrrole, above. For more information contact us at info@libretexts.org or check out our status page at https://status.libretexts.org. Let's look at our previous example, benzene: Each double bond (π bond) always contributes 2 $$\pi$$ electrons. As we discuss these examples, some patterns will emerge. Have questions or comments? Its first 2 $$\pi$$ electrons fill the lowest energy orbital, and it has 4 $$\pi$$ electrons remaining. We know that all carbons in furan are sp2 hybridized. Furan has 6 $$\pi$$ electrons and fulfills the 4n+2 rule. They appear to have only two double bonds, thus only four p orbital electrons perpendicular to the ring. First, why is aromaticity an issue? Presence of (4n + 2) π e… In general, resonance structures delocalize electrons, and thus stabilize a structure. Some aromatic compounds with a heteroatom (an atom other than C or H) in the ring have a five-membered ring. Unfortunately, reasons for not discussing this too much in an introductory class will also emerge; understanding aromaticity even at an elementary level beyond "like benzene" requires understanding orbitals. Basic Structure of Benzene Because of the aromaticity of benzene, the resulting molecule is planar in shape with each C-C bond being 1.39 Å in length and each bond angle being 120°. This is entirely wrong. Thus they actually have six electrons that are in p orbitals perpendicular to the ring. Note that all annulenes have the general formula CxHx (where x must be an even number), and that the term does not in itself imply aromatic character. In a cyclic hydrocarbon compound with alternating single and double bonds, each carbon is attached to 1 hydrogen and 2 other carbons. Benzene, C 6 H 6, is the least complex aromatic hydrocarbon, and it was the first one named as such. As you may recall, benzene is the prototype aromatic system. The compound is cyclic, but it does not have a benzene ring Compounds that contain benzene rings in their structures are commonly reformed to … However, as you go on in organic chemistry you will find a variety of compounds called aromatic, even though they are not so obviously benzene derivatives. The special feature of benzene is that it is more stable than we might expect. Legal. A bond is known to be polar when the centers of positive and negative charges of the molecule do not coincide with each other. These 4 fill in the orbitals of the succeeding energy level. The following figure shows 3D representations of both "forms" of 18-annulene; they have been rotated so you view them "edge on". If the compound does not meet all the following criteria, it is likely not aromatic. Each carbon atom in the hexagonal cycle has four electrons to share. In fact, some programs will calculate a planar structure for it. Benzene, as a common aromatic compound, can be converted to an unstable antiaromatic 8π-electron intermediate through two-electron reduction. Cyclooctatetraene has eight, and is not aromatic; its dianion has ten, and is aromatic. Watch the recordings here on Youtube! The top structure is the planar form that one might naively expect; the other is the slightly distorted structure, which closely corresponds to what is actually observed. What is Polarity? That is considerably more than the simple sp2 bond angle of 120 deg. These molecules are called heterocyclic compounds because they contain 1 or more different atoms other than carbon in the ring. As we will see here, it is not easy to give a more complete definition that is satisfying in an introductory course. How Can You Tell Which Electrons are $$\pi$$ Electrons? Its first 2 $$\pi$$ electrons fill the lowest energy orbital, and it has 4 $$\pi$$ electrons The compound has a benzene ring; It is aromatic. It is common to start by saying that aromatic compounds are compounds related to benzene. Watch the recordings here on Youtube! Yes, it is. These include pyrrole, C4H5N, and furan, C4H4O: What do these compounds share with benzene and pyridine that makes them aromatic? Then, set this number equal to $$4n+2$$ and solve for $$n$$. A molecule is aromatic if it is cyclic, planar, completely conjugated compound with 4n + 2 π electrons. Therefore, each carbon is $$sp^2$$ hybridized and has a p orbital. [ "article:topic", "bruner", "showtoc:no" ], An interesting example is 1,3,5,7-cyclooctatetraene (often simply called cyclooctatetraene), C, cyclooctatetraene dianion, shown with the circle that denotes an aromatic ring, The cyclopropenyl (or "cyclopropenium") cation, C. Now, the non-aromatic character of cyclooctatetraene alone is not too hard to explain. Unless otherwise noted, LibreTexts content is licensed by CC BY-NC-SA 3.0. The p orbitals on neighboring C atoms overlap sideways, a type of bonding known as π (pi) bonding. ), Virtual Textbook of Organic Chemistry. As we will see here, it is not easy to give a more complete definition that is satisfying in an introductory course. Perhaps the toughest part of Hückel's Rule is figuring out which electrons in the compound are actually $$\pi$$ electrons. It is common to start by saying that aromatic compounds are compounds related to benzene. Benzene is an aromatic compound, as the C-C bonds formed in the ring are not exactly single or double, rather they are of intermediate length. According to Huckel rule, for a ring to be aromatic it should have the following property: 1. Another simple rule to determine if an atom is sp2 hybridized is if an atom has 1 or more lone pairs and is attached to an sp2 hybridized atom, then that atom is sp2 hybridized also. Turns out that it is fairly easy for cyclooctatetraene to gain 2 electrons, forming the dianion, C8H82-. The molecule is planar (all atoms in the molecule lie in the same plane), The molecule has 4n+2 $$π$$ electrons (n=0 or any positive integer). Why? Notice how oxygen has 2 lone pairs of electrons. The resonance stabilization in benzene is considerably more than we might expect for simply having some double bonds near each other. So we might suggest that the bond angle strain of the planar form more than compensates for any gain due to aromaticity. (sometimes referred to as a "closed loop of six electrons", which he also calls the "aromatic sextet"). One of the benzene structures has a ring in the center of the hexagon, the ring depicts an aromatic compound. This video provides a very nice tutorial on how to determine an atom's hybridization.

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